m:n mapping tables), e.

To create an index for a selected schema, in SQL, in the Navigator tab, select Indexes from the object type drop-down list, click Object submenu , and select Create Object.

There are cases where you can create a unique. .

This statement creates a unique index.

To edit an index for a selected schema, right-click a table object in the Navigator tab, and select Edit.

. . "using index" will create a unique index with the same name as the PK constraint, but when we disable the constraint, the unique index is also gone.

21 Managing Indexes.

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. On the Table Designer menu, select Indexes/Keys.

This restriction guarantees that rows with identical index keys always map into.

To create an index for a selected schema, in SQL, in the Navigator tab, select Indexes from the object type drop-down list, click Object submenu , and select Create Object.

Use the CREATE INDEX statement to create an index on: One or more columns of a table, a partitioned table, an index-organized table, or a cluster. Description of the create an index illustration This figure shows the following fields: Name, Type.

Jan 24, 2022 · 1. .

2), you can choose to keep old index entries to search on original content by using the ASYNCHRONOUS_UPDATE parameter string option.
You can follow guidelines for managing indexes.
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21 Managing Indexes.

To edit an index for a selected schema, right-click a table object in the Navigator tab, and select Edit. . Use the CREATE INDEX statement to create an index on: One or more columns of a table, a partitioned table, an index-organized table, or a cluster.

Select the new index in the Selected Primary/Unique Key or Index text box. . Improve this answer. Jan 24, 2022 · 1. Alternatively, you can define UNIQUE integrity constraints on.

ALTER TABLE Colleges DROP INDEX college_index; Here, the SQL command removes an index named college_index from the Colleges table.

CREATE UNIQUE INDEX indexName ON tableName (column1, column2, ); Parameters. .

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Then create (or use existing) nonunique indexes to enforce the constraint.

To fix the issue I was trying to drop existing index and re-create it: ALTER TABLE table1 drop constraint test_uk1; DROP INDEX test_uk1; CREATE UNIQUE INDEX test_uk1 ON table1 (UPPER (column1)); ALTER.

This restriction guarantees that rows with identical index keys always map into.